2024 In fig. 6.2 bac 90° and ad  bc. then

In fig. 6.2 bac 90° and ad  bc. then

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WebAug 5, 2024 · In the given figure, ∠A = 90°, AD ⊥ BC. If BD = 2 cm and CD = 8 cm, find AD. (2012; 2024D) Solution: ∆ADB ~ ∆CDA … [If a perpendicular is drawn from the vertex of the right angle of a rt. ∆ to the hypotenuse then As on both sides of the ⊥ are similar to the whole D and to each other ∴ … [∵ Sides are proportional AD 2 = BD , DC WebIn Fig. 7.238, ∠BAC = 90° and AD ⊥ BC. Then, BD. CD = _________. Q. In figure, ∠BAC=90∘ and segment AD⊥BC. Prove that AD2 =BD×DC. [3 MARKS] Q. In the figure given below, …

In Fig. 6.2, ∠BAC = 90° and AD BC. Then, - Cuemath

WebMar 22, 2024 · Ex 6.2, 1 In figure (i) ,DE BC. Find EC in (i) It is given that DE II BC Hence , / = / Putting the values 1.5/3 = 1/ 1.5 EC = 1 3 EC = (1 3)/1.5 EC = 2 cm Ex 6.2, 1 In figure (ii), … WebIn the given figure, ∠BAC = 90 0 and AD⊥BC. Then, (a) BC.CD = BC 2 (b) AB.AC = BC 2 (c) BD.CD = AD 2 (d) AB.AC = AD 2 triangles class-10 1 Answer 0 votes answered Sep 4, 2024 by AmirMustafa (60.4k points) selected Sep 16, 2024 by Vikash Kumar Best answer (c) BD.CD = AD2 In ∆ BDA and ∆ADC, we have: hayley hasselhoff plus size model

2. In the given figure, angle BAC = 90° and AD …

WebJun 28, 2024 · In the figure, if ∠BAC = 90° and AD ⊥ BC. Then, (A) BD . CD = BC 2 (B) AB . AC = BC 2 (C) BD . CD = AD 2 (D) AB . AC = AD 2 Solution: (C) In ∆ABC, ∠B + ∠BAC + ∠C = … WebAug 5, 2024 · AB 2 + BC 2 = (6$\sqrt{3}$) 2 + (6) 2 = 108 + 36 = 144 = (12) 2 AB 2 + BC 2 = AC 2 ∴ ∠B = 90° … [Above theorem. Question 43. In the given figure, BL and CM are … WebIn figure, if ∠BAC =90° and AD⊥BC. Then, (a) BD.CD = BZC² (b) AB.AC = BC² (c) BD.CD=AD² (d) AB.AC =AD² Solution: c) BD.CD=AD² Explanation: From ∆ADB and ∆ADC, According to … hayley erin general hospital

In Fig., ∠BAC = 90°, AD ⊥ BC and ∠BAD = 50°, then ∠ACD is (a) 50° …

In fig 6.2 angle BAC =90° and AD perpendicular to BC - Brainly

WebMar 29, 2024 · Ex 6.2, 4 In figure, DE AC and DF AE. Prove that, prove that 𝐵𝐹/𝐹𝐸 = 𝐵𝐸/𝐸𝐶 Given: DE II AC and DF II AE To prove: 𝐵𝐹/𝐹𝐸=𝐵𝐸/𝐸𝐶 Proof: From (1) and (2) 𝐵𝐹/𝐹𝐸=𝐵𝐸/𝐸𝐶 Hence proved Next: Ex 6.2, 5 Important → Ask a doubt Chapter 6 Class 10 Triangles Serial order wise Ex 6.2 WebWe observe that ADB is a right angle triangle with D equal to 90 degrees. By Pythagorean theorem, AD² + BD² = AB² (h)² + (x/2)² = (x)². h² + x²/4 = x². h² = x² - x²/4. h² = [(4-1)/4]x². h² … hayley shepherdWebJun 29, 2024 · In the given figure, ∠BAC = 90° and AD⊥BC. Then, (a) BC.CD = BC2 (b) AB.AC = BC2 (c) BD.CD = AD2 (d) AB.AC = AD2 triangles class-10 1 Answer +1 vote answered … hayley mills movies on netflix

"WebAug 1, 2024 · Solution: The figure is attached below In Triangle ABC, angle BAC = 90 degree and AD is perpendicular to BC Given in the question a perpendicular is drawn AD on BC from angle BAC which is 90 degree So, these two triangles ABD and CAD are similar By Corresponding part of Similar Triangles (CPST), " - In fig. 6.2 bac 90° and ad  bc. then

In fig. 6.2 bac 90° and ad  bc. then

In an equilateral triangle ABC (Fig. 6.2), AD is an altitude.

WebIn figure, if ∠BAC =90° and AD⊥BC. Then, (a) BD.CD = BZC² (b) AB.AC = BC² (c) BD.CD=AD² (d) AB.AC =AD² Solution: c) BD.CD=AD² Explanation: From ∆ADB and ∆ADC, According to the question, we have, ∠D = ∠D = 90° (∵ AD ⊥ BC) ∠DBA = ∠DAC [each angle = 90°- ∠C] Using AAA similarity criteria, ∆ADB ∼ ∆ADC BD/AD = AD/CD BD.CD = AD 2 2. WebExample 5 : Observe Fig. 6.30 and then find P. Fig. 6.30 Solution : In ABC and PQR, Rationalised 2024-24 92 MATHEMATICS. AB 3.8 1 , BC 6 1 CA 3 3 1 and RQ 7.6 2 QP 12 2 PR 6 3 2. AB BC CA That is, RQ QP PR

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WebAug 18, 2024 · In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then, (A) BD . CD = BC 2 (B) AB . AC = BC 2 (C) BD . CD = AD 2 (D) AB . AC = AD 2 triangles ncert class-10 Please log in or … WebClick here👆to get an answer to your question ️ In fig if ADE = ABC ,then show that ADE∼ ABC and AD = 6.8 cm, AE = 8.6 cm, BE = 2.4 cm and BC = 5.5 cm Find DE

WebGiven, ABC is an equilateral triangle with AD as altitude. We have to find the value of 4AD². We know that in an equilateral triangle all the sides are of equal length. Let AB = BC = AC = x units ----- (1) Let AD = h units ----- (2) In an equilateral triangle, the altitude AD bisects BC. So, BD = CD = BC/2 = x/2 WebMar 29, 2024 · Example 10 In figure, ∠ ACB = 90° and CD ⊥ AB. Prove that BC2/AC2=BD/AD Given:- ΔCAB, ∠ ACB = 90° And CD ⊥ AB To Prove :- BC2/AC2=BD/AD Proof : From theorem 6.7, If a perpendicular is drawn from the vertex of the right angle to the hypotenuse then triangles on both sides of the Perpendicular are similar to the whole triangle and to ...

WebMar 16, 2024 · Ex 6.6, 4 In Fig. 6.59, ABC is a triangle in which ABC < 90 and AD BC. Prove that AC2 = AB2 + BC2 2 BC . BD. WebMar 7, 2024 · In the given figure, angle BAC = 90° and AD perpendicular BC. Then, A)BC.CD = BC² B)AB.AC =BC² C) BD.CD = AD² D)AB.AC = AD² Answer: Option C) BD.CD = AD² …

WebMay 18, 2024 · In Fig., ∠BAC = 90° and AD ⊥ BC. The number of right triangles in the figure is (A) 1 (B) 2 (C) 3 (D) 4 geometry class-6 1 Answer +1 vote answered May 18, 2024 by Varun01 (53.6k points) selected May 22, 2024 by Subnam01 (C) 3 We have, ∠BAC = 90° and AD ⊥ BC ∵ ∠BDA = ∠CDA = ∠BAC = 90° ∴ There are 3 right triangles formed in the given …

hayley podschunWebMar 29, 2024 · Transcript. Question 3 In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then, BD . CD = BC2 (B) AB . AC = BC2 (C) BD . CD = AD2 (D) AB . AC = AD2 From Theorem 6.7, If a … Transcript. Question 4 The lengths of the diagonals of a rhombus are 16 cm and … hayley mills movies on internetWebApr 11, 2024 · In the given figure, if ∠BAC = 90° and AD⏊BC. Then, (A) BD.CD = AD2 (B) AB.AC = AD2 (C) BD.CD = AD2 (D) AB.AC = AD2 Ans: The correct option is (C): BD·CD = AD2 In ΔADB and ΔADC, It is given that ∠BDA = ∠ADC = 90° ∠B = ∠DAC = (90°- C) Now, by AA similarity criterion $\triangle \mathrm {ADB} \sim \triangle \mathrm {CDA}$ hayley singapore actressWebByju's Answer Standard X Mathematics Criteria for Similarity of Triangles In the given ... Question In the given figure, if ∠ADE= ∠B, show that ΔADE ∼ΔABC. If AD = 3.8 cm, AE = 3.6 cm, BE = 2.1 cm and BC = 4.2 cm, find DE. Solution In ΔADE and ΔABC, ∠A= ∠A (Common angle) ∠ADE= ∠B (Given) So by AA similarity, triangles are similar. So, by CPCT, hayley mills recent photosWebSolution Verified by Toppr Given:- Let ABCD be the quadrilateral circumscribing the circle with centre O. The quadrilateral touches the circle at point P,Q,R and S. To prove:- … hayley spear facebookWebIn the given figure, `angle BAC=90^(@) and AD bot BC`.then, hayley westenra twitterWebIn Fig. 6.13, ∠BAC = 90°, AD ⊥ BC and ∠BAD = 50°, then ∠ACD is (a) 50° (b) 40° (c) 70° (d) 60° 25. If one angle of a triangle is equal to the sum of the other two angles, the triangle is (a) obtuse (b) acute (c) right (d) equilateral 26. hayleyxofficial