2024 Evaluate using identities 103×97

Evaluate using identities 103×97

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WebSep 11, 2024 · Evaluate using a suitable identity :95 multiplied by 97 - 1470541. Brainly User Brainly User 11.09.2024 Math Secondary School ... 95 is multiplied by 97. Find. we need to evaluate 95×97 using a suitable identity. Solution. We have, 95×97. here we can write 95 as (100-5) and similarly 97 will become (100-3) WebUsing the identity [ Using the identity, ( x + a) ( x + b) = x 2 + ( a + b) x + a b] = 10000 + 100 – 12. = 10088. Concept: Expansion of (x + a) (x + b) Is there an error in this question …

x Using suitable identities, evaluate the following: 104 × 97 - BYJU

WebUsing identity evaluate: 107 x 103. Asked by Topperlearning User 04 Jun, 2014, 01:23: PM ... Evaluate 99 2 using suitable identity. Asked by Topperlearning User 04 Jun, … WebUsing suitable identities, evaluate the following: 98×103 Solution We have, 98×103=(100−2)(100+3) = (100)2+(−2+3)100+(−2)×3 = 10000+100−6 = 10094 [using … flub antonym

Evaluate the following by using the suitable identity: 48^2

WebMay 26, 2024 · Formula : a² - b² = ( a + b ) ( a - b ) Solution : Step 1 of 2 : Write down the given expression The given expression is 103 × 97 Step 2 of 2 : Find the value of the … WebUsing the identity (a + b) (a - b) = a² - b² Here a = 2 and b = 0.07 ∴ (2 + 0.07) (2 - 0.07) = 2² - (0.07)² = 3.9951 Try This: Evaluate using suitable identities: (i) 271² - 29², (ii) 294 × … flubar the wool man

Evaluate the following by using identities: 103 × 97 - Toppr

WebMar 25, 2024 · Here, we cannot just manually evaluate the given mathematical term, we have to use suitable identities. So, = (103)² = (100 + 3)² = (100)² + (2 × 100 × 3) + (3)² = (10000) + (600) + (9) = 10609 (This will be considered as the final result.) Used formula : (a+b)² = a² + 2ab + b² Hence, the value of (103)² is 10609 Find Math textbook solutions? WebSolution The correct option is C 2756 52×53 can be written as (50+2)(50+3) We know that, (x+a)(x+b) =x2+(a+b)x+ab, Here, x=50,a =2 and b =3. ∴ (50+2)(50+3) =(50)2+(2+3)×50+2×3 = 2500+(5×50)+6 = 2500+250+6 = 2756 Suggest Corrections 8 Similar questions Q. Question 86 (viii) Using suitable identities, evaluate the following: 52×53 Q. greenearth energy limitedWebMay 5, 2024 · 103 × 97 We can write it as (100 + 3) × (100 - 3) = (100 + 3)(100 - 3) Using the identity : Putting x = 100 and y = 3 Hope this helps!! If you have any doubt regarding … flubadub chub chicago

"WebWe will use the following algebraic Identities to evaluate the given expressions. (x + y) 3 = x 3 + y 3 + 3xy (x + y) (x - y) 3 = x 3 - y 3 - 3xy (x - y) (i) (99) 3 = (100 - 1) 3 Identity: Here we can use (x - y) 3 = x 3 - y 3 - 3xy (x - y) Let us substitute x = 100, y = 1 (99) 3 = (100) 3 - (1) 3 - 3 (100) (1) (100 - 1) = 1000000 - 1 - 300 × 99 " - Evaluate using identities 103×97

Evaluate using identities 103×97

Evaluate the following by using identities: (97)^2 - Toppr

WebEvaluate the following products without multiplying directly: (i) 103 × 107 . Solution: 103×107=(100+3)×(100+7) Using identity, [(x+a)(x+b)=x2+(a+b)x+ab . NCERT Solution For Class 9 Maths Chapter 2- Polynomials. Here, x=100 a=3 b=7 . We. get, 103×107=(100+3)×(100+7) WebClick here👆to get an answer to your question ️ Evaluate the following using suitable identities. (102)^3 ... Join / Login. Question . Evaluate the following using suitable …

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WebFeb 26, 2024 · Polynomial Identities Questions for Competitive Exams Question 1. Simplify the following: ( a 2 + 2) 2 − ( a − 2) ( a + 2) ( a 2 + 4) Solution: For ( a 2 + 2) 2 apply formula of ( a + b) 2 For ( a − 2) ( a + 2) apply formula of ( a 2 − b 2) Substitute and multiple all the terms, you will get = a 4 + 4 a 2 + 4 − a 4 + 16 = 4 a 2 + 20 Question 2. WebSolution: Using algebraic Identities, (x + a) (x + b) = x 2 + (a + b)x + ab (a + b) (a - b) = a 2 - b 2 (i) 103 × 107 Identity: (x + a) (x + b) = x 2 + (a + b)x + ab 103 × 107 = (100 + 3) (100 + 7) Substituting x = 100, a = 3, b = 7 in the above identity, we get = (100) 2 + (3 + 7) (100) + (3) (7) = 10000 + 1000 + 21 = 11021 (ii) 95 × 96

WebUsing suitable identity , evaluate the following (i) `103^(3)` (ii) `101xx102`(iii) `999^(2)` WebFeb 11, 2024 · Evaluate using identities:- (a) 103 X 97 (b) (0.99) (0.99) (c) 105 X 105 X 105 Advertisement aahnapushpa15 Answer: Step-by-step explanation: ) (103) (97) = …

Web1. Use the formula (x + a) (x + b) = x2 + x (a + b) + ab to identity to find the following products. (i) (x + 5) (x + 6) (ii) (x + 7) (x + 10) (iii) (x + 9) (x + 8) (iv) (x + 3) (x + 8) 2. Use the formula (x + a) (x - b) = x2 + x (a – b) – ab to identity to find the following products. (i) (x + 3) (x – 7) (ii) (x + 5) (x – 2) (iii) (t + 7) (t – 5) WebMar 18, 2024 · ⇒ 103 × 97 = ( 100 + 3) ( 100 − 3), we substituted the values of a and b in ( a + b) ( a − b). We know that the formula, ( a + b) ( a − b) = a 2 − b 2, now we will express ( 100 + 3) ( 100 − 3) as 100 2 − 3 2 . ⇒ 103 × 97 = 100 2 − 3 2 and 100 2 = 10000 , 3 2 = 9 ⇒ 10000 − 9 ⇒ 9991 Hence, the value of 103 × 97 = 9991.

WebMar 22, 2024 · Transcript Ex 2.5, 2 Evaluate the following products without multiplying directly: (iii) 104 96 104 96 = (100 + 4) (100 4) Using the identity (x + y) (x y) = x2 y2 where x = 100 , y = 4 = (100)2 (4)2 = 10000 16 = 9984 Next: Ex 2.5, 3 (i) → Ask a doubt Chapter 2 Class 9 Polynomials Serial order wise Ex 2.5

WebEvaluate the following by using the suitable identity: 48 2 Easy Solution Verified by Toppr We know (a−b) 2=a 2+b 2−2ab Using the identity, we get 48 2 =(50−2) 2 =50 2+2 2−2×50×2 =2500+4−200 =2304 Hence, the answer is 2304 Was this answer helpful? 0 0 Similar questions Evaluate the following by using the identities: 92 2 Medium View … flubbed in a sentenceWebSolution Verified by Toppr Correct option is B) Let us rewrite (102) 3 as (100+2) 3 Now using the identity (a+b) 3=a 3+b 3+3ab(a+b), we get (100+2) 3=100 3+2 3+[(3×100×2)(100+2)] =1000000+8+(600×102) =1000000+8+61200 =1061208 Hence, (102) 3=1061208 Was this answer helpful? 0 0 Similar questions Evaluate the following: i 528 … green earth energy ctWebUsing suitable identities, evaluate the following: 104×97 Solution We have, 104×97=(100+4)(100−3) = (100)2+(4−3)100+4×(−3) = 10000+100−12 = 10088 [using … green earth endless knotWebWrite the expression 103 × 97 in terms of an algebraic identity. The expression 103 × 97 is written as (100 + 3) (100 – 3) ... Hence, 103 × 97 = (100 + 3) (100 – 3) = 100 2 – 3 2. Therefore, the given expression can also be written as : (100 + 3) (100 – 3) = 100 2 – 3 2. Quiz on Algebraic Identities. Q 5. flub a wordWebJun 22, 2024 · Evaluate each of the following by using identities: (i)`103\ xx\ 97` (ii) `103\ xx\ 103` - YouTube This is the Solution of Question From RD SHARMA book of CLASS 9 CHAPTER … flub a dub chub\\u0027s in chicagoWebEvaluate using suitable identity (ii) `97 xx 103` Doubtnut 2.68M subscribers Subscribe 81 Share 6.5K views 4 years ago To ask Unlimited Maths doubts download Doubtnut from -... green earth energy corporationWebIn algebra, a quadratic equation (from Latin quadratus 'square') is any equation that can be rearranged in standard form as where x represents an unknown value, and a, b, and c represent known numbers, where a ≠ 0. (If a = 0 and … flubaroo install